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15x^2-57x-12=0
a = 15; b = -57; c = -12;
Δ = b2-4ac
Δ = -572-4·15·(-12)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-63}{2*15}=\frac{-6}{30} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+63}{2*15}=\frac{120}{30} =4 $
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